Wiki-Quellcode von Lösung Definitions- und Wertemengen
Zuletzt geändert von Henrik Horstmann am 2026/10/19 21:33
Zeige letzte Bearbeiter
| author | version | line-number | content |
|---|---|---|---|
| 1 | (%class="abc"%) | ||
| 2 | 1. | ||
| 3 | {{formula}}\begin{aligned} | ||
| 4 | &D_f = \mathbb{R}^* \quad \text{und} \quad W_f = \mathbb{R}^* \\ | ||
| 5 | &D_g = \mathbb{R} \quad \text{und} \quad W_g = [4,\infty[ \\ | ||
| 6 | &f(g(x)) = \frac{1}{x^2+4} \\ | ||
| 7 | &g(x) \neq 0 \iff x^2+4 \neq 0 \iff x^2 \neq -4 \implies x \in \mathbb{R} \\ | ||
| 8 | &D_{f \circ g} = \mathbb{R} \quad \text{und} \quad W_{f \circ g} = \left]0,\frac{1}{4}\right] | ||
| 9 | \end{aligned}{{/formula}} | ||
| 10 | 1. | ||
| 11 | {{formula}}\begin{aligned} | ||
| 12 | &D_f = \mathbb{R}_+ \quad \text{und} \quad W_f = \mathbb{R}_+ \\ | ||
| 13 | &D_g = \mathbb{R} \quad \text{und} \quad W_g = \mathbb{R} \\ | ||
| 14 | &f(g(x)) = \sqrt{2x - 6} \\ | ||
| 15 | &g(x) \geq 0 \iff 2x - 6 \geq 0 \iff 2x \geq 6 \iff x \geq 3 \\ | ||
| 16 | &D_{f \circ g} = [3,\infty[ \quad \text{und} \quad W_{f \circ g} = [0,\infty[ | ||
| 17 | \end{aligned}{{/formula}} | ||
| 18 | 1. | ||
| 19 | {{formula}}\begin{aligned} | ||
| 20 | &D_f = \mathbb{R} \setminus \{2\} \quad \text{und} \quad W_f = \mathbb{R}^* \\ | ||
| 21 | &D_g = \mathbb{R} \quad \text{und} \quad W_g = [-1,\infty[ \\ | ||
| 22 | &f(g(x)) = \frac{1}{x^2-3} \\ | ||
| 23 | &g(x) = 2 \iff x^2-1 = 2 \iff x^2 = 3 \iff x = \pm\sqrt{3} \\ | ||
| 24 | &D_{f \circ g} = \mathbb{R} \setminus \{-\sqrt{3},\sqrt{3}\} \\ | ||
| 25 | &\qquad W_{f \circ g} = \left]-\infty,-\frac{1}{3}\right[ \cup \left]0,\infty\right[ | ||
| 26 | \end{aligned}{{/formula}} |